In what time will the interest on $R s 1456.80$ be $R s 182.10$ at $5 % p . a .$

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Solution

$P = R s 1456.80 R = 5 % p . a . S I = R s 182.10 T = \frac{S I \times 100}{P \times R} = \frac{182.10 \times 100}{1456.80 \times 5} = 2.5 y e a r s$

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