Question

In what volume of water, $20g$ of $NaOH$ is to be dissolved, such that $400ml$ of this solution exactly neutralizes $4.9g$ of $H_2{SO}_4$?

Answer 1

4.9g of sulfuric acid is $\frac{4.9}{98}$ = 0.05mol,

The neutalization reaction can be written as

$NaOH+H_2{SO}_4\to {Na}_2{SO}_4+H_{2}O$

Change in Free Energy is given as

ΔG = -15.3kJ

Change in Enthalpyis given as

ΔH = -15.6kJ

So, we need 0.1mol of NaOH (4 grams) to neutralize 0.05mol of sulfuric acid

Then 20g/Qml = 4g/400ml

Q = 400 x 20 / 4 = 2000

So, we add the 20g of NaOH to make 2000ml or 2L of basic solution.