Question

In Wheat stones network P = 2 $\Omega$, Q = 2 $\Omega$ , R = 2$\Omega$ and S = 3 $\Omega$ . The resistance with which S is to shunted in order that the bridge may be balanced is

• A. $4\Omega$
• B. $1\Omega$
• C. $6\Omega$
• D. $2\Omega$

Answer 1

The correct option is C

$6\Omega$

$\frac{P}{Q}=\frac{R}{\frac{SX}{S+X}}\Rightarrow \frac{2}{2}=\frac{2}{\frac{3\times X}{3+X}}\Rightarrow \frac{3X}{3+X}=23X=6+2X\Rightarrow X=6\Omega$