Question

In which case, a spontaneous reaction is possible at any temperature?

• A. $\Delta H-ve,\Delta S+ve$
• B. $\Delta H-ve,\Delta S-ve$
• C. $\Delta H+ve,\Delta S+ve$
• D. none of these

Answer 1

The correct option is A $\Delta H-ve,\Delta S+ve$

For a spontaneous process $\Delta G=-ve$

$\Delta G<0$

Also, $\Delta G=\Delta H-T\Delta S$

$\Delta H=-ve$

$\Delta S=+ve$

Thus, the given condition reveals $\Delta G=-ve$.

Hence, option A is correct.