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Mixture

In which case...

Question

In which case, purity of the substance is $100 %$ ?

1

mole of

C a C O_{3}

gave

11.2 L

C O_{2}

(at

S T P

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1

mole of

M g C O_{3}

gave

40.0 g

M g O

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1

mole of

N a H C O_{3}

gave

4 g

H_{2} O

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1

mole of

C a (H C O_{3})_{2}

gave

1

mole

C O_{2}

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Solution

The correct option is C $1$ mole of $M g C O_{3}$ gave $40.0 g$ $M g O$ .
Assuming all are $100 %$ pure, then,
$1$ mole of $C a C O_{3}$ should give $22.4$ L $C O_{2}$ (at $S T P$ ).
$1$ mole of $M g C O_{3}$ should give $40.0$ g $M g O$ .
$1$ mole of $N a H C O_{3}$ should give $9$ g $H_{2} O$ .
$1$ mole of $C a (H C O_{3})_{2}$ should give $2$ mol $C O_{2}$ .

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22.4

C a C O_{3}

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%

L i_{2} C O_{3}

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2

50 %

C a (H C O_{3})_{2}

1

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C a (H C O_{3})_{2} Δ - \to C a O + H_{2} O + 2 C O_{2}

M g C O_{3}

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M g C O_{3} + 2 H C l \to M g C l_{2} + C O_{2} + H_{2} O

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