Question

In which case, shape of the molecule is pyramidal?

• A. $N(C{H}_3{)}_3$
• B. $N(Si{H}_3{)}_3$
• C. Both (A) and (B)
• D. None of these

Answer 1

The correct option is A $N(C{H}_3{)}_3$

In $N(Si{H}_3{)}_3$, due to back bonding from N to Si, the lone pair of N is out of hybridisation and is changed into p-coordinate bond. So, hybridisation changes from $s{p}^{3}tos{p}^2$ and shape changes from pyramidal to planar.