181

You visited us 181 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Electron Affinity

In which case...

Question

In which case the energy released in minimum and why?

A)Cl -> Cl^-

B) P -> P^-

C) N-> N^-

D) C -> C^-

Open in App

Solution

The electron affinity (EA) is the energy required/released to add one electron to an atom.
For example:

a) Cl to Cl^-
Cl + e^- → Cl^-
ΔE = - 349 kJ/mol

EA values can be found in tables on the web or in your textbook. EA (generally) increases as you move left to right across the periodic table, from the alkali metals to the halogens. If the products are more stable, a large amount of energy will be released during the process and EA will be a large negative number.

Suggest Corrections

Similar questions

$P C l_{5} ⇌ P C l_{3} + C l_{2}$ in the reversible reaction, the moles of $P C l_{5}$ , $P C l_{3}$ and $C l_{2}$ are a, b and c respectively at equilibrium and total pressure is P, then value of $K_{p}$ is:

P C l_{5} (g)

\to

P C l_{3} (g) + C l_{2} (g)

in the reversible reaction, the moles of

P C l_{5}, P C l_{3} a n d C l_{2}

are a, b and c respectively and total pressure at equilibrium is P, then value of

K_{p}

is:

Q. Given:
Pt (s) |

C l^{-}

(

C_{1}

) |

C l_{2}

(g)(

P_{1}

atm) ||

C l_{2}

(g)(

P_{1}

atm)|

C l^{-}

(

C_{2}

)| Pt (s)
Identify in which of the following condition working of cell takes place:

B C l_{3} + N H_{4} C l 140^{\circ} C - --- \to P

Which of the following is correct about P?

P {C l}_{5} ⇌ P {C l}_{3} + {C l}_{2}

in the reversible reaction the moles of

P {C l}_{5}, P {C l}_{3}, {C l}_{2}

are

a, b

and

c

respectively and total pressure is

P

then value of

K_{p}

is:

Join BYJU'S Learning Program

In which case the energy released in minimum and why? A)Cl -> Cl- B) P -> P- C) N-> N- D) C -> C-

In which case the energy released in minimum and why?

A)Cl -> Cl^-

B) P -> P^-

C) N-> N^-

D) C -> C^-