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Question

In which case, the number of molecules of water maximum?

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> NEET 2018

A
103 mol of water
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B
0.00224 L of water vapours at 1 atm and 273 K
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C
18 mL of water
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D
0.18 mL of water
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Solution

The correct option is C 18 mL of water
(a) Mass of water = d×V =1×18 =18 g
Moles of water =wH2OMH2O =1818= 1 mol
Molecules of water =mole× NA =1× NA =NA

(b) Molecules of water =mole× NA =0.1818 NA
=102 NA

(c) Molecules of water =mole× NA =103 NA

(d) Moles of water =0.0022422.4 =104 mol
Molecules of water =mole× NA =103 NA

Hence, the correct answer is option (a).

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