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Oxides of Sulphur

In which case...

Question

In which case there is change in oxidation number:

Aqueous solution of

C r O_{4}^{2 -}

is acidified

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S O_{2}

gas is passed into

C r_{2} O_{7}^{2 -}

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C r_{2} O_{7}^{2 -}

solution is made alkaline

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C r O_{2} C l_{2}

is dissolved in

N N a O H

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Solution

The correct option is A $S O_{2}$ gas is passed into $C r_{2} O_{7}^{2 -}$
Reaction:
$C r_{2} O_{7}^{2 -} + 6 + S O_{2} + 4 \to S O_{4}^{2 -} + 6 + C r_{+ 3}^{3 +}$

Suggest Corrections

Similar questions

C O_{2}

C r O_{4}^{2 -}

C r_{2} O_{7}^{2 -}

C r O_{4}^{2 -} (a q) C O_{2} - - \to C r_{2} O_{7}^{2 -}

S O_{2}

S

S O_{2}

K_{2} C r_{2} O_{7}

S

S O_{2}

S O_{2}

{C r_{2} O_{7}}^{2 -}

C r^{2 +}

C r

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