You visited us 1 times! Enjoying our articles? Unlock Full Access!

Hydrogen Bonding

In which case...

Question

In which case will the hydrogen bond not be observed?

H_{3} O_{2}^{-}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

H_{2} O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

H_{5} O_{2}^{+}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

H_{3} O^{+}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $H_{3} O^{+}$
In hydronium ion, a dative bond exists between $H^{+}$ ion and $H_{2} O$ . Thus, it does not have hydrogen bonding.

Suggest Corrections

Similar questions

H_{5} O_{2}^{+}

H_{3} O^{+}

H_{5} O_{2}^{-}

H_{7} O_{3}^{+}

H_{2} P O_{4}^{-}

H_{3} P O_{4} + H_{2} O \to H_{3} O^{+} + H_{2} P O_{4}^{-}

H_{2} P O_{4}^{-} + H_{2} O \to H P O_{4}^{2 -} + H_{3} O^{+}

H_{2} P O_{4}^{-} + O H^{-} \to H_{3} P O_{4} + O^{2 -}

H_{2} P O_{4}^{-}

H_{2} {P O}_{4}^{-}

H_{3} {P O}_{4} + H_{2} O \to H_{3} O^{+} + H_{2} {P O}_{4}^{-}

H_{2} {P O}_{4}^{-} + H_{2} O \to H {P O}_{4}^{2 -} + H_{3} O^{+}

H_{2} {P O}_{4}^{-} + {O H}^{-} \to H_{3} {P O}_{4} + O^{2 -}

O_{2}, O_{2}^{+}, O_{2}^{-}

O_{2}^{2 -}

[F e (C N)_{6}]^{4 -}

[F e (C N)_{6}]^{3 -}

[F e (C N)_{6}]^{3 -}

[F e (C N)_{6})]^{4 -}

Join BYJU'S Learning Program