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Stoichiometric Calculations

In which case...

Question

In which cases are the law of conservation of mass followed?

A

10

g

C a C O_{3}

on heating gives

0.1

mole

C a O

and

2.24

L

C O_{2}

at NTP

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B

1

mole

N_{2}

and

1

mole

H_{2}

combine to form

2

moles of

N H_{3}

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C

0.2

mole

S O_{2}

combines with

3.2

g

O_{2}

to form

0.2

moles

S O_{3}

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D

1

g

H_{2}

combines with

0.5

g

O_{2}

to form

1.5

g

H_{2} O

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Solution

The correct options are
A $10$ g $C a C O_{3}$ on heating gives $0.1$ mole $C a O$ and $2.24$ L $C O_{2}$ at NTP
C $0.2$ mole $S O_{2}$ combines with $3.2$ g $O_{2}$ to form $0.2$ moles $S O_{3}$
The Law of Conservation of Mass:
In a chemical change total mass remains conserved, i.e. mass before reaction is always equal to mass after reaction.
$10$ g $C a C O_{3}$ ( $0.1$ mole) on heating gives $0.1$ mole $C a O$ ( $5.6$ g) and $2.24 L$ $C O_{2}$ ( $0.1$ mole = $4.4$ g) at $N T P$ .
$0.2$ mole ( $12.8$ g) $S O_{2}$ combines with $3.2 g$ $O_{2}$ ( $0.1$ mole) to form $0.2$ moles ( $16$ g) $S O_{3}$ .
$2 S O_{2} + O_{2} \to 2 S O_{3}$

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