The correct option is B Clockwise, 135o
Given:
∠FE1E=45o
Observing the figure, we can conclude that side BC of ABCD corresponds to side FG of EFGH.
So, to get the angle by which ABCD has been rotated around (0,0) to obtain EFGH, we have to calculate the angle between side BC and side FG around (0,0), i.e., ∠BE1F.
We know that ∠BE1F+∠FE1E=180o
∠BE1F=180o−45o=135o
Now, counterclockwise rotation by 135o will take rectangle ABCD to the fourth quadrant, but EFGH is in the first quadrant.
Therefore, the rectangle ABCD has been rotated clockwise by 135∘ around (0, 0) to obtain image EFGH.