In which of the following adduct is formed most easily?

(C H_{3})_{2} O + B F_{3}

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(S i H_{3})_{2} O + B F_{3}

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(C H_{3})_{2} O + B B r_{3}

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(S i H_{3})_{2} O + B B r_{3}

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Solution

The correct option is C $(C H_{3})_{2} O + B B r_{3}$
$(C H_{3})_{2} O + B B r_{3}$
No back bonding in both $(C H_{3})_{2} O$ and $B B r_{3}$ . Hence adduct formation is most easy. Back bonding reduces both acidic as well as basic character and hence reduces the possibility of adduct formation.

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