In which of the following arrangements, the given sequence is not strictly according to the property indicated against it?

H_{2} O < H_{2} S < H_{2} S e < H_{2} T e

; increasing

p K_{a}

values

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{N H}_{3} < {P H}_{3} < A s H_{3} < S b H_{3}

; increasing acidic character

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{C O}_{2} < S i O_{2} < S n O_{2} < P b O_{2}

; increasing oxidising power

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H F < H C l < H B r < H I

; increasing acidic strength

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Solution

The correct option is D $H_{2} O < H_{2} S < H_{2} S e < H_{2} T e$ ; increasing $p K_{a}$ values
The following sequence is not strictly according to the property indicated against it.
$H_{2} O < H_{2} S < H_{2} S e < H_{2} T e$ ; increasing $p K_{a}$ values.

Th correct sequence is:
$H_{2} O > H_{2} S > H_{2} S e > H_{2} T e$ ; decreasing $p K_{a}$ values.

In Hydrides, as we move top to bottom, acidic nature increases so with the increase in the acidity from top to bottom, the $K_{a}$ value increases and $p K_{a}$ value decreases.

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Similar questions

F_{2}, C l_{2}, B r_{2}, I_{2}

H F, H C l, H B r, H I

N H_{3}, P H_{3}, A s H_{3}, S b H_{3}, B i H_{3}

Arrange the following in the order of property indicated for each set:

$F_{2}, C l_{2}, B r_{2}, I_{2}$ - increasing bond dissociation enthalpy.

HF,HCl, HBr, HI- Increasing acid strength.

$N H_{3}, P H_{3}, A s H_{3}, S b H_{3}, B i H_{3}$ - increasing base strength.

H F, H C l, H B r, H I

H_{2} O, H_{2} S, H_{2} S e, H_{2} T e

H_{2} O, H_{2} S, H_{2} S e, H_{2} T e

H F, H C l, H B r, H I

N H_{3}, P H_{3}, A S H_{3}, S b H_{3}, B i H_{3}

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