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Question

In which of the following arrangements, the order is according to the property indicated against it.
(I) I<Br<F<Cl increasing electron gain enthalpy
(II) Li<Na<K<Rb increasing metallic radius
(III) B<C<N<O increasing first ionization energy
(IV) Al3+<Mg2+<Na+<F− increasing ionic size

A
I, II and III
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B
I and III only
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C
I, II and IV
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D
I and II only
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Solution

The correct option is C I, II and IV
(I) Electron gain enthalpy of halogen:
I<Br<F<Cl
Halogens have maximum electron gain enthalpy in the corresponding period and it becomes less negative down the group.
However, the electron gain enthalpy of fluorine is less than that of chlorine. It is due to small size of fluorine, there is a strong electronic repulsion for incoming eletron.
(II) On going down the group, size of atom increases, metallic radii also increase.
(III) On moving left to right in a period, ionisation energy increases but ionisation energy of nitrogen is more than oxygen due to half filled stable configuration. Hence, order of ionization energy is B<C<O<N
(IV) Ionic radii order : Anionic>Neutral> Cationic
Therefore, increasing order of ionic size for isoelectronic species:
Al3+<Mg2+<Na+<F

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