In which of the following case, $E_{a}$ of the backward reaction is greater than that of the forward reaction?

A + 10 k c a l \to B, E_{a} = 50 k c a l

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A + 20 k c a l \to B, E_{a} = 40 k c a l

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A + 40 k c a l \to B, E_{a} = 10 k c a l

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A - 40 k c a l \to B, E_{a} = 20 k c a l

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Solution

The correct option is D $A - 40 k c a l \to B, E_{a} = 20 k c a l$
$Δ H = E_{a f} - E_{a b}$ .
In the reaction given in option D, The actiation energy of product B is greater than the activation energy of reactant A.

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