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Question

In which of the following cases hydrolysis takes place through SN2andSN1 mechanism, respectively?

A
P4O10,SiCl4
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B
NCl3,NF3
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C
SiCl4,SiF4
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D
SF4,TeF6
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Solution

The correct option is D SF4,TeF6
The maximum hybridization state possible for group 16 elements is sp3d2. SF4 undergoes hydrolysis through SN2 mechanism as in the transition state, it is possible to accommodate the incoming nucleophile. Sulphur has a total of 6 valence electrons, out of which only 4 are taking part in bonding. The hybridization is sp3d. It has an oxidation state of +4 while, a maximum of +6 is possible. Here, due to empty d orbital, a nucleophile can attack the S atom. However, the hybridization of Te in TeF6 is sp3d2. Since, no more d -orbitals are available for the attack of nucleophile, it will undergo SN1 mechanism. Thus, TeF6 undergoes hydrolysis through SN1 mechanism.

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