In which of the following cases is the oxidation state of $N$ atom wrongly calculated?

\begin{matrix} C o m p o u n d & O x i d a t i o n s t a t e N H_{4} C l & - 3 \end{matrix}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\begin{matrix} C o m p o u n d & O x i d a t i o n s t a t e {(N_{2} H_{5})}_{2} S O_{4} & + 2 \end{matrix}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\begin{matrix} C o m p o u n d & O x i d a t i o n s t a t e {M g}_{3} N_{2} & - 3 \end{matrix}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\begin{matrix} C o m p o u n d & O x i d a t i o n s t a t e N H_{2} O H & - 1 \end{matrix}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $\begin{matrix} C o m p o u n d & O x i d a t i o n s t a t e {(N_{2} H_{5})}_{2} S O_{4} & + 2 \end{matrix}$
In $\begin{matrix} C o m p o u n d & O x i d a t i o n s t a t e {(N_{2} H_{5})}_{2} S O_{4} & + 2 \end{matrix}$ the oxidation state of $N$ atom is wrongly calculated.
Let X be the oxidation state of N in $(N_{2} H_{5})_{2} S O_{4}$
$2 X + 5 = + 1$
$2 X = - 4$
$X = - 2$

Suggest Corrections

Similar questions

In which of the following elements +1 oxidation state is more stable than +3 oxidation state?

The effective atomic number of central metal ion is wrongly calculated in the following complex?

The oxidation state of $N$ in $N H_{4} N O_{3}$ is

In which of the following $+ 1$ oxidation state is more stable than $+ 3$ ?

Join BYJU'S Learning Program