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Question

In which of the following cases, the reaction goes farthest to completion?

A
AB (K=103)
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B
PQ (K=102)
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C
A+BC+D (K=10)
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D
X+YXY (K=101)
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Solution

The correct option is A AB (K=103)
Higher the equilibrium constant, faster the rate of reaction
A+BC+D
K=[C][D][A][B]
To complete the reaction fastest, the numerator of RHS must be higher.
In reaction AB the value of equilibrum constant is K=103 which is higher than other equilibrium constants of reactions given in the options.
hence, the reaction AB will complete fast.

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