7
You visited us
7
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard X
Chemistry
Electrolytic Cells
In which of t...
Question
In which of the following cells salt bridge is not needed ?
A
P
b
|
P
b
S
O
4
(
s
)
|
H
2
S
O
4
|
P
b
O
2
(
s
)
|
P
b
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
C
d
|
C
d
O
(
s
)
|
K
O
H
(
a
q
)
|
N
i
O
2
(
s
)
|
N
i
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
F
e
(
s
)
|
F
e
O
(
s
)
|
K
O
H
(
a
q
)
.
N
i
2
O
3
(
s
)
|
N
i
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
Z
n
|
Z
n
S
O
4
|
|
C
u
S
O
4
|
C
u
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct options are
A
P
b
|
P
b
S
O
4
(
s
)
|
H
2
S
O
4
|
P
b
O
2
(
s
)
|
P
b
B
C
d
|
C
d
O
(
s
)
|
K
O
H
(
a
q
)
|
N
i
O
2
(
s
)
|
N
i
C
F
e
(
s
)
|
F
e
O
(
s
)
|
K
O
H
(
a
q
)
.
N
i
2
O
3
(
s
)
|
N
i
Suggest Corrections
0
Similar questions
Q.
Construct the cells in which the following reactions are taking place. Which of the electrodes shall act as anode (negative electrode) and which one as cathode (positive electrode)?
(a)
Z
n
+
C
u
S
O
4
=
Z
n
S
O
4
+
C
u
(b)
C
u
+
2
A
g
N
O
3
=
C
u
(
N
O
3
)
2
+
2
A
g
(c)
Z
n
+
H
2
S
O
4
=
Z
n
S
O
4
+
H
2
(d)
F
e
+
S
n
C
l
2
=
F
e
C
l
2
+
S
n
Q.
Which of the following metals will couple to provide a higher cell potential for a galvanic cell?
Z
n
2
+
(
a
q
)
+
2
e
−
→
Z
n
(
s
)
;
E
0
=
−
0.76
V
C
u
2
+
(
a
q
)
+
2
e
−
→
C
u
(
s
)
;
E
0
=
0.34
V
N
i
2
+
(
a
q
)
+
2
e
−
→
N
i
(
s
)
;
E
0
=
−
0.25
V
P
b
2
+
(
a
q
)
+
2
e
−
→
P
b
(
s
)
;
E
0
=
−
0.13
V
F
e
2
+
(
a
q
)
+
2
e
−
→
F
e
(
s
)
;
E
0
=
−
0.44
V
Q.
Consider the following reactions :
C
u
S
O
4
+
F
e
→
F
e
S
O
4
+
C
u
F
e
S
O
4
+
Z
n
→
Z
n
S
O
4
+
F
e
Among these:
Q.
The standard reduction potential at STP
(
25
∘
C
and 1 atm) of the following half cells are found as below.
P
b
2
+
a
q
+
2
e
−
→
P
b
(
s
)
E
0
=
−
0.121
V
P
b
O
2
(
s
)
+
4
H
+
(
a
q
)
+
S
O
2
−
4
(
a
q
)
+
2
e
−
→
P
b
S
O
4
(
s
)
+
2
H
2
O
E
0
=
1.71
V
P
b
4
+
(
a
q
)
+
2
e
−
→
P
b
2
+
(
a
q
)
E
0
=
1.689
V
For the cell
P
b
S
O
4
(
s
)
+
2
e
−
→
P
b
(
s
)
+
S
O
2
−
4
(
a
q
)
,
The
E
0
is missing but it is found that in an aqueous solution of
H
2
S
O
4
having a pH=1.7, when
P
b
S
O
4
(
s
)
is put, then at saturated condition
Solubility of
P
b
S
O
4
=
5
×
10
−
5
M
o
l
/
L
(
T
a
k
e
2.303
R
T
F
=
0.06
a
n
d
l
o
g
2
=
0.3
)
List-I contains questions and List-II contains their answers.
List-I
List-II
What is the
E
0
(in V) for the half-cell
(I)
P
b
S
O
4
(
s
)
+
2
e
−
→
P
b
(
s
)
+
S
O
2
−
4
(
a
q
)
?
(P) -0.168
What is the
E
0
c
e
l
l
(in V) of a lead storage battery? It has
(II) the cell reaction as
P
b
(
s
)
+
P
b
O
2
(
s
)
+
2
H
2
S
O
4
(
a
q
)
→
2
P
b
S
O
4
(
s
)
+
2
H
2
O
(
l
)
(Q) 0.7
What is the
E
0
(in V) for the half cell
(III)
P
b
O
2
(
s
)
+
4
H
+
(
a
q
)
+
4
e
−
→
P
b
(
s
)
+
2
H
2
O
(
I
)
(R) 2.0
K
s
p
is the equilibrium constant for the reaction
(IV)
P
b
O
2
(
s
)
+
4
H
+
(
a
q
)
⇌
P
b
4
+
(
a
q
)
+
2
H
2
O
(
l
)
(S) -0.068
What is the value of
E
o
(in V)
?
(T) -0.31
(U) 2.02
Which of the following options has the correct combination considering the reactions in List-I and their answers in List-II?
Q.
The standard reduction potential at STP
(
25
∘
C
and 1 atm) of the following half cells are found as below.
P
b
2
+
a
q
+
2
e
−
→
P
b
(
s
)
E
0
=
−
0.121
V
P
b
O
2
(
s
)
+
4
H
+
(
a
q
)
+
S
O
2
−
4
(
a
q
)
+
2
e
−
→
P
b
S
O
4
(
s
)
+
2
H
2
O
E
0
=
1.71
V
P
b
4
+
(
a
q
)
+
2
e
−
→
P
b
2
+
(
a
q
)
E
0
=
1.689
V
For the cell
P
b
S
O
4
(
s
)
+
2
e
−
→
P
b
(
s
)
+
S
O
2
−
4
(
a
q
)
,
The
E
0
is missing but it is found that in an aqueous solution of
H
2
S
O
4
having a pH=1.7, when
P
b
S
O
4
(
s
)
is put, then at saturated condition
Solubility of
P
b
S
O
4
=
5
×
10
−
5
M
o
l
/
L
(
T
a
k
e
2.303
R
T
F
=
0.06
a
n
d
l
o
g
2
=
0.3
)
List-I contains questions and List-II contains their answers.
List-I
List-II
What is the
E
0
(in V) for the half-cell
(I)
P
b
S
O
4
(
s
)
+
2
e
−
→
P
b
(
s
)
+
S
O
2
−
4
(
a
q
)
?
(P) -0.168
What is the
E
0
c
e
l
l
(in V) of a lead storage battery? It has
(II) the cell reaction as
P
b
(
s
)
+
P
b
O
2
(
s
)
+
2
H
2
S
O
4
(
a
q
)
→
2
P
b
S
O
4
(
s
)
+
2
H
2
O
(
l
)
(Q) 0.7
What is the
E
0
(in V) for the half cell
(III)
P
b
O
2
(
s
)
+
4
H
+
(
a
q
)
+
4
e
−
→
P
b
(
s
)
+
2
H
2
O
(
I
)
(R) 2.0
K
s
p
is the equilibrium constant for the reaction
(IV)
P
b
O
2
(
s
)
+
4
H
+
(
a
q
)
⇌
P
b
4
+
(
a
q
)
+
2
H
2
O
(
l
)
(S) -0.068
What is the value of
E
o
(in V)
?
(T) -0.31
(U) 2.02
Which of the following options has the correct combination considering the reactions in List-I and their answers in List-II?
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Electrolytic Cells
CHEMISTRY
Watch in App
Explore more
Electrolytic Cells
Standard X Chemistry
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app