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Question

In which of the following compounds does the central atom violate the octet rule?
(Given: Atomic number,Se=34, As=33, B=5, N=7)

A
NH3
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B
SeF2
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C
BF3
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D
AsF3
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Solution

The correct option is C BF3
The lewis dot structure of given molecules are as follow:

The central atoms N, Se and As in NH3, SeF2 and AsF3 respectively have 8 valence electrons. But in the case of BF3, boron has an incomplete octet of only 6 electrons in its valence shell and hence violates the octet rule.

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