Question

In which of the following compounds iron has lowest oxidation number?

• A. $FeS{O}_4.(N{H}_4{)}_{2}S{O}_4.6H_{2}O$
• B. $K_4\left[Fe\right(CN{)}_6]$
• C. $F{e}_{2}O$
• D. $F{e}_2{O}_3$

Answer 1

The correct option is C $F{e}_{2}O$

$FeS{O}_4.(N{H}_4{)}_{2}S{O}_4.6H_{2}O$ : oxidation state of Fe = +2

$K_4\left[Fe\right(CN{)}_6]$ : oxidation state of Fe = 6-4 = +2

$F{e}_{2}O$ : oxidation state of Fe = +1

$F{e}_2{O}_3$ : oxidation state of Fe = +3

Hence, $F{e}_{2}O$ has lowest oxidation state.