Question

In which of the following compounds, nitrogen exhibits highest oxidation state?

• A. $N_{3}H$
• B. $N{H}_{2}OH$
• C. $N_2{H}_4$
• D. $N{H}_3$

Answer 1

The correct option is A $N_{3}H$

Oxidation states of Nitrogen in the following compounds:

$N_{3}H$ - oxidation state of nitrogen $=\frac{-1}{3}$

$N{H}_{2}OH$ - oxidation state of nitrogen $=-1$

$N_2{H}_4$ - oxidation state of nitrogen $=-2$

$N{H}_3$ - oxidation state of nitrogen $=-3$

Hence, option A is correct.