Question

In which of the following compounds, nitrogen exhibits highest oxidation state ?

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> AIPMT PRE- EXAMINATION PAPER 2012

• A. $N_{3}H$
• B. $N_2{H}_4$
• C. $N{H}_3$
• D. $N{H}_{2}OH$

Answer 1

The correct option is A $N_{3}H$

Oxidation state of H is +1
Oxidation state of O is -2

Compound	Oxidation number of nitrogen
$N_2{H}_4$	$=-2$
$N{H}_3$	$=-3$
$N_{3}H$	$=-1/3$
$N{H}_{2}OH$	$=-1$

Hence, option (c) is correct.