Question

In which of the following compounds oxidation state of chlorine has two different values?

• A. $CaC{l}_2$
• B. $NaCl$
• C. $CaOC{l}_2$
• D. $CC{l}_4$

Answer 1

Answer: (C)

$CaOC{l}_2$

Ionic compounds can exist in equillibrium with the constituting ions as:

A. $CaC{l}_2\to C{a}^{2+}+2C{l}^{-}$

Oxidation state of $Cl$ is -1

B. $NaCl\to N{a}^{+}+C{l}^{-}$

Oxidation state of $Cl$ is -1

C. $CaOC{l}_2\to C{a}^{2+}+OC{l}^{-}+C{l}^{-}$

Oxidation state of $Cl$ is -1 in $C{l}^{-}$ and in $OC{l}^{-}$ it is: $-2+x=-1orx=+1$

D. $CC{l}_4$ is covalent and thus oxidation of all $Cl$ is same.