In which of the following coordination entities the magnitude of - 0 CFSE in the octahedral field will be maximum- Atomic number of Co-27

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Standard XII

Chemistry

Crystal Field Split in Octahedral Complexes

In which of t...

Question

In which of the following coordination entities the magnitude of $Δ_{0}$ (CFSE in the octahedral field) will be maximum? (Atomic number of $C o = 27$ )

[C o (C N)_{6}]^{3 -}

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[C o (C_{2} O_{4})_{3}]^{3 -}

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[C o (H_{2} O)_{6}]^{3 +}

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[C o (N H_{3})_{6}]^{3 +}

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Solution

The correct option is C $[C o (C N)_{6}]^{3 -}$
Since CFSE depends on strength of the ligand which depends on the electronegativity of the donor atom, therefore the strength of the ligand is in order of CN^->NH₃>C₂O₄^2->H₂O. [Lesser electronegativity means easy electron-donating capacity and hence stronger ligand].

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The colour of the coordination compounds depends on the crystal field splitting. What will be the correct order of absorption of wavelength of light in the visible region, for the complexes, $[C o (N H_{3})_{6}]^{3 +}, [C o (C N)_{6}]^{3 -}, [C o (H_{2} O)_{6}]^{3 +}$
$[C o (N H_{3})_{6}]^{3 +}, [C o (C N)_{6}]^{3 -}, [C o (H_{2} O)_{6}]^{3 +}$
(a) $[C o (C N)_{6}]^{3 -} > [C o (N H_{3})_{6}]^{3 +} > [C o (H_{2} O)_{6}]^{3 +}$
(b) $[C o (N H_{3})_{6}]^{3 +} > [C o (H_{2} O)_{6}]^{3 +} > [C o (N H_{3})_{6}]^{3 +}$
(c) $[C o (H_{2} O)_{6}]^{3 +} > [C o (N H_{3})_{6}]^{3 +} > [C o (C N)_{6}]^{3 -}$
(d) $[C o (C N)_{6}]^{3 -} > [C o (N H_{3})_{6}]^{3 +} > [C o (H_{2} O)_{6}]^{3 +}$

In which of the following coordination entities, the magnitude of $Δ_{\circ}$ [CFSE in octahedral field] will be maximum?

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In which of the following coordination entities the magnitude of Δ0 (CFSE in the octahedral field) will be maximum? (Atomic number of Co=27)

In which of the following coordination entities the magnitude of $Δ_{0}$ (CFSE in the octahedral field) will be maximum? (Atomic number of $C o = 27$ )