In which of the following equations is x and y in inverse proportion ?

xy = 6

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y = x+3

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$\frac{y}{4} = x$

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x= y-2

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Solution

The correct option is A
xy = 6

xy = 6 $\Rightarrow y = \frac{6}{x}$ and x and y are in inverse proportion.

y = x + 3, neither a case of direct proportion nor a case of inverse proportion.

$\frac{y}{4} = x \Rightarrow y = 4 x$ a case of direct proportion.

x = y - 2 , neither a case of direct proportion nor a case of inverse proportion.

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In which of the following equations is x and y in inverse proportion ?

The correct option is A xy = 6 xy = 6 ⇒y=6x and x and y are in inverse proportion. y = x + 3, neither a case of direct proportion nor a case of inverse proportion. y4=x⇒y=4x a case of direct proportion. x = y - 2 , neither a case of direct proportion nor a case of inverse proportion.