You visited us 1 times! Enjoying our articles? Unlock Full Access!

Addition of Inert Gas at Constant Pressure

In which of t...

Question

In which of the following equilibrium reactions. the equilibrium would shift to right side, if total pressure is decreased?

N_{2} + 3 H_{2} ⇌ 2 N H_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

H_{2} + I_{2} ⇌ 2 H I

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N_{2} O_{4} ⇌ 2 N O_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

H_{2} + C l_{2} ⇌ 2 H C l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $N_{2} O_{4} ⇌ 2 N O_{2}$
When pressure decreases the reaction will shift in the direction to increase the number of moles.
Hence option $C$ is correct.

Suggest Corrections

Similar questions

(K_{c})

H_{2} + I_{2} ⇌ 2 H I

N_{2} + 3 H_{2} ⇌ 2 N H_{3}

50

1000

N_{2} + 6 H I ⇌ 2 N H_{3} + 3 I_{2}

If the equilibrium constant of the reaction $2 H I ⇌ H_{2} + I_{2}$ is $0.25$ , then the

equilibrium constant of the reaction $H_{2} + I_{2} ⇌ 2 H I$ would be

N_{2} + 3 H_{2} ⇌ 2 N H_{3},

N_{2} : H_{2}

N_{2} + 3 H_{2} \to 2 N H_{3} - K_{1}

N_{2} + O_{2} \to 2 N O - K_{2}

H_{2} + 1 / 2 O_{2} \to H_{2} O - K_{3}

3 H_{2} + 5 / 2 O_{2} \to 2 N O + 3 H_{2} O

K_{1}, K_{2}, K_{3}

If the equilibrium constant of the reaction $2 H I ⇌ H_{2} + I_{2}$ is $0.25$ , then the

equilibrium constant of the reaction $H_{2} + I_{2} ⇌ 2 H I$ would be

Join BYJU'S Learning Program