In which of the following expressions, prime factorization has been done?

(i) 24 = 2 × 3 × 4
(ii) 56 = 1 × 7 × 2 × 2 × 2
(iii) 70 = 2 × 5 × 7
(iv) 54 = 2 × 3 × 9

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Solution

(i) 24 = 2 × 3 × 4 is not a prime factorisation as 4 is not a prime number.
(ii) 56 = 1 × 7 × 2 × 2 × 2 is not a prime factorisation as 1 is not a prime number.
(iii) 70 = 2 × 5 × 7 is a prime factorisation as 2, 5, and 7 are prime numbers.
(iv) 54 = 2 × 3 × 9 is not a prime factorisation as 9 is not a prime number.

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Similar questions

2 \times 3 \times 4

7 \times 2 \times 2 \times 2

2 \times 5 \times 7

2 \times 3 \times 9

In which of the following expressions, prime factorization has been done?

(a) 24 = 2 × 3 × 4 (b) 56 = 7 × 2 × 2 × 2

In which of the following expressions, prime factorization has been done:

(i) $24 = 2 \times 3 \times 4$
(ii) $56 = 7 \times 2 \times 2 \times 2$
(iii) $70 = 2 \times 5 \times 7$
(iv) $54 = 2 \times 3 \times 9$

Take away:

$(i) \frac{6}{5} x^{2} - \frac{4}{5} x^{3} + \frac{5}{6} + \frac{3}{2} x from \frac{x^{3}}{3} - \frac{5}{2} x^{2} + \frac{3}{5} x + \frac{1}{4}$

$(i i) \frac{5 a^{2}}{2} + \frac{3 a^{3}}{2} + \frac{a}{3} - \frac{6}{5} from \frac{1}{3} a^{3} - \frac{3}{4} a^{2} - \frac{5}{2}$

$(i i i) \frac{7}{4} x^{3} + \frac{3}{5} x^{2} + \frac{1}{2} x + \frac{9}{2} from \frac{7}{2} - \frac{x}{3} - \frac{x^{2}}{5}$

$(i v) \frac{y^{3}}{3} + \frac{7}{3} y^{2} + \frac{1}{2} y + \frac{1}{2} from \frac{1}{3} - \frac{5}{3} y^{2}$

$(v) \frac{2}{3} a c - \frac{5}{7} a b + \frac{2}{3} b c from \frac{3}{2} a b - \frac{7}{4} a c - \frac{5}{6} b c$

\frac{2 \times 6}{2} = \frac{8}{2} + \frac{4}{2}

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