Question

In which of the following molecule/ion, all the bond lengths are not of equal lengths?

• A. $Si{F}_4$
• B. $S{F}_4$
• C. $Xe{F}_4$
• D. $B{H}_4^{-}$

Answer 1

The correct option is B $S{F}_4$

$Si{F}_4$ is $s{p}^3$ hybridised and hence all bond lengths are equal.

$S{F}_4$ is $s{p}^{3}d$ hybridised and has a trigonal bipyramidal geometry, in this type of geometry the axial bonds are longer than the equatorial bonds and hence all the bond lengths are not equal.

$Xe{F}_4$ is $s{p}^3{d}^2$ hybridised and hence all the bond lengths are equal.

$B{H}_4^{-}$ is $s{p}^3$ hybridised and hence all the bond lengths are equal.