Question

In which of the following molecule, the number of possible $\angle XAX$ angles is maximum in the anionic part of their solid state? [$A:$ Central atom, $X:$ surrounding atom]

• A. $PB{r}_5$
• B. $N_2{O}_5$
• C. $PC{l}_5$
• D. $C{l}_2{O}_6$

Answer 1

Answer: (C)

$PC{l}_5$

$PB{r}_5\left(s\right)\to [PB{r}_4{]}^{+}+B{r}^{-}$

$N_2{O}_5\left(s\right)\to N{O}_2^{+}+N{O}_3^{-}\left(s{p}^2\right)$

$2PC{l}_5\left(s\right)\to PC{l}_4^{+}+PC{l}_6^{-}\left(s{p}^3{d}^2\right)$

$C{l}_2{O}_6\left(s\right)\to Cl{O}_2^{+}+Cl{O}_4^{-}\left(s{p}^3\right)$

XAX angles are maximum in the anionic part of their solid-state is $PC{l}_5$

Hence option C is correct.