Question

In which of the following molecule, the number of possible $\angle XAX$ angles is maximum in the anionic part of their solid state? [$A:$ central atom, $X:$ surrounding atom]

• A. $PB{r}_5$
• B. $N_2{O}_3$
• C. $PC{l}_5$
• D. $C{l}_2{O}_6$

Answer 1

The correct option is C $PC{l}_5$

$PB{r}_5\left(s\right)\to [PB{r}_4{]}^{+}+B{r}^{-}{N}_2{O}_5(s)\to N{O}_2^{+}+N{O}_3^{-}(s{p}^2\left)PC{l}_5\right(s)\to PC{l}_4^{+}+PC{l}_6^{-}(s{p}^3{d}^2\left)C{l}_2{O}_6\right(s)\to Cl{O}_2^{+}+Cl{O}_4^{-}(s{p}^3)$


Hence $PC{l}_6^{-}$ has maximum number of possible $\angle XAX$ angles.