Question

In which of the following molecules, central atom is $s{p}^3$ hybridised?

• A. $PC{l}_3,BC{l}_3,NC{l}_3$
• B. $SnC{l}_4,SC{l}_4,CC{l}_4$
• C. $N{H}_4^{+},PC{l}_3,BC{l}_3$
• D. $N{H}_2^{-},PC{l}_3,N{H}^{2-}$

Answer 1

The correct option is D $N{H}_2^{-},PC{l}_3,N{H}^{2-}$


$H=\frac{1}{2}[V+M-C+A]$

where,
H = Number of orbitals involved in hybridization.
V = Valence electrons of the central atom.
M = Number of monovalent atoms linked to the central atom.
C = Charge of the cation.
A = Charge of the anion.

$N{H}_2^{-}=\frac{1}{2}[5+2+1]=4=s{p}^3$
$PC{l}_3=\frac{1}{2}[5+3]=4=s{p}^3$
$N{H}^{2-}=\frac{1}{2}[5+1+2]=4=s{p}^3$