Question

In which of the following molecules/ions all the bonds are not equal?

• A. $S{F}_4$
• B. $Si{F}_4$
• C. $Xe{F}_4$
• D. $B{F}_4^{-}$

Answer 1

The correct option is A $S{F}_4$


In $S{F}_4,$ $S$ has $s{p}^{3}d$ - hybridization. Thus, it contains two axial and two equatorial bonds to give a see-saw structure.
So, in $S{F}_4$ all the bonds are not equal.