In which of the following options is the central metal ion not correctly matched with its respective hybridisation and geometry?

K_{2} [P d B r_{2} C l_{2}]

s p^{3}

, tetrahedral

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[N i (C O)_{4}]

s p^{3}

, tetrahedral

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[F e (N H_{3})_{6}] S O_{4}

s p^{3} d^{2}

, octahedral

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[F e (N H_{3})_{6}]_{2} (S O_{4})_{3}

d^{2} s p^{3}

, octahedral

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Solution

The correct option is A $K_{2} [P d B r_{2} C l_{2}]$ , $s p^{3}$ , tetrahedral
(a) $K_{2} [P d B r_{2} C l_{2}]$ : $d s p^{2}$ , square planar geometry.
(b) $[N i (C O)_{4}]$ : $s p^{3}$ , tetrahedral.
(c) $[F e (N H_{3})_{6}] S O_{4}$ : $s p^{3} d^{2}$ , octahedral.
Here $F e$ is in (+2) oxidation state and $N H_{3}$ acts as weak field ligand which does not cause pairing. So outer d orbital will participate in hybridisation.
(d) $[F e (N H_{3})_{6}]_{2} (S O_{4})_{3}$ : $d^{2} s p^{3}$ , octahedral.
Here $F e$ is in (+3) oxidation state and $N H_{3}$ acts as strong field ligand which cause pairing. So inner d orbital will participate in hybridisation.

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