Question

In which of the following orbitals, nodal plane is absent?

• A. $4s$
• B. $4d_{z^2}$
• C. $4d_{x^2-y^2}$
• D. $4d_{zx}$

Answer 1

Answer: (A), (B)

The correct options are
A $4s$
B $4d_{z^2}$

For $s-$orbital, $l=0$, no nodal plane.
for $d_{z^2}$ - orbital, $l=2,2$ conical node, no nodal plane.