In which of the following oxoanions the oxidation state of central atom is not same as that of its group number in periodic table?

M n O_{4}^{-}

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C r_{2} O_{7}^{2 -}

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V O_{4}^{3 -}

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F e O_{4}^{2 -}

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Solution

The correct option is C $F e O_{4}^{2 -}$
Electronic configuration of ions and their oxidation no.
$M n O_{4}^{-} = + 7; [A r]^{18} 3 d^{5} 4 s^{2} = 7$ .
$C r O_{7}^{2 -} = + 6; [A r]^{18} 3 d^{5} 4 s^{1} = 6$ .
$V O_{4}^{3 -} = + 5; [A r]^{18} 3 d^{3} 4 s^{2} = 5$ .
$F e O_{4}^{2 -} = + 6; [A r]^{18} 3 d^{6} 4 s^{2} = 8$ .
So, Fe compound is the right answer.

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In which of the following oxoanions the oxidation state of central atom is not same as that of its group number in periodic table?

The correct option is C FeO2−4Electronic configuration of ions and their oxidation no.MnO−4=+7;[Ar]183d54s2=7.CrO2−7=+6;[Ar]183d54s1=6.VO3−4=+5;[Ar]183d34s2=5.FeO2−4=+6;[Ar]183d64s2=8.So, Fe compound is the right answer.