In which of the following pairs, hydrogen bonding is not possible?

N H_{3}, N H_{3}

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N H_{3}, C H_{4}

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H_{2} O, C H_{3} O H

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H F, H_{2} O

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Solution

The correct option is A $N H_{3}, C H_{4}$
Hydrogen bonding is possible when highly electronegative (EN) elements $N, O, F$ are present in the molecules along with $H$ .
Out of the given options, $C H_{4}$ can not undergo $H -$ bonding because the EN difference between $C$ and $H$ is not appreciable.
Hence, option $B$ is correct.

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Similar questions

Q. The order of increasing acidic strength of

C H_{4}, N H_{3}, H_{2} O, H F

is :

Q. The correct order of magnitude of bond angles among the compounds

C H_{4}, N H_{3} a n d H_{2} O

Question 04

Hydrogen bonds are formed in many compounds e.g., $H_{2} O, H F, N H_{3}$ . The boiling point of such compounds depends to a extent on the strength of hydrogen bond and the number of hydrogen bonds. The correct decreasing order of the boiling points above compounds is

(a) $H F > H_{2} O > N H_{3}$

(b) $H_{2} O > H F > N H_{3}$

(d) $N H_{3} > H_{2} O > H F$

Q. Explain the hydrogen bonding in molecules of

H F,

H_{2} O

and

N H_{3}

The order of boiling point of $N H_{3}, H_{2} O, H F a n d P H_{3}$ is

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In which of the following pairs, hydrogen bonding is not possible?

The correct option is A NH3,CH4Hydrogen bonding is possible when highly electronegative (EN) elements N, O, F are present in the molecules along with H.Out of the given options, CH4 can not undergo H−bonding because the EN difference between C and H is not appreciable.Hence, option B is correct.