Question

In which of the following pairs, the hybridisation of central atoms is same, but geometry is not the same?

• A. $S{O}_3,C{O}_3^{2-}$
• B. $S{O}_3^{2-},N{H}_3$
• C. $PC{l}_5,POC{l}_3$
• D. $Xe{F}_2,IC{l}_3$

Answer 1

Answer: (D)

$Xe{F}_2,IC{l}_3$

A) Hybridization of $S{O}_3=s{p}^2$

Hybridization of $C{O}_3^{2-}=s{p}^2$

B) Hybridization of $S{O}_3^{2-}=s{p}^3$

Hybridization of $N{H}_3=s{p}^3$

C) Hybridization of $PC{l}_5=s{p}^{3}d$

Hybridization of $POC{l}_3=s{p}^3$

D) Hybridization of $Xe{F}_2=s{p}^3{d}^2$

Hybridization of $IC{l}_3=s{p}^3{d}^2$

Image 1 $S{O}_3^{2-}$ shape is Trigonal Planar

Image 2 $C{O}_3^{2-}$ shape is Trigonal Planar.

Image 3 $S{O}_3^{2-}$ shape is Trigonal Pyramidal.

Image 5 $N{H}_3$ shape is Trigonal Pyramidal.

Image 6 $PC{l}_5$ shape is Trigonal Bipyramidal.

Image 7 $POC{l}_3$ shape is Tetrahedral.

Image 8 $Xe{F}_2$ shape is Square Pyramidal.

Image 9 $IC{l}_3$ shape is T-shape.