The correct option is B β−−decay
In α−decay, xAy→ x−2By−4+α
In β−decay, xAy→ x+1By+ −1β0
In β+decay, xAy→ x−1By+ +1β0
For γ−decay, there will be no change in the number of protons, as only energy is released in the form of γ radiations.
Therefore, the only case in which the number of protons increases is β−decay.
Hence, option (B) is correct.