In which of the following reaction a primary amine with loss of carbon is produced?
A
R−CONH2+NaOHBr2→
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B
R−CONH2LiAlH4→
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C
R−CONH2NaBH4→
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D
All of the above
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Solution
The correct option is AR−CONH2+NaOHBr2→ a) Amine is formed but with one carbon atom lesser than present in the amide. It is called Hoffmann bromamide degradation. R−CONH2+NaOHBr2→R−NH2
b)
c) NaBH4 reduces aldehydes, ketones and acid halides but can not reduce amides to amines.