In which of the following reaction $H_{2} O$ acts as a Bronsted acid?

H_{2} O (l) + N H_{3} (a q) ⇌ O H_{(} a q) + N H^{+} 4 (a q)

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H_{2} O (l) + H_{2} S_{(} a q) ⇌ H_{3} O_{(}^{+} a q) + H S_{(}^{-} a q)

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H_{2} O (l) + H_{2} O_{(} a q) ⇌ H_{3} O_{(}^{+} a q) + O H_{(}^{-} a q)

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H^{+} (a q) + O H_{(}^{-} a q) ⇌ H_{2} O (l)

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Solution

The correct option is B $H_{2} O (l) + N H_{3} (a q) ⇌ O H_{(} a q) + N H^{+} 4 (a q)$
Bronstead acid is proton donor. Bronstead base is proton acceptor.

In the following reaction, $H_{2} O$ acts as a Bronsted acid and gives a proton to react with a base ( $N H_{3}$ ).

$H_{2} O + N H_{3} ⇌ O H^{-} + N H_{4}^{+}$

In the following reaction, $H_{2} O$ acts as a Bronsted base and accepts a proton to react with a acid ( $H_{2} S$ ).

$H_{2} O + H_{2} S \to H_{3} O^{+} + H S^{-}$

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H_{2} O_{(l)} + H_{2} O_{(l)} ⇌ H_{3} O_{(a q)}^{+} + O H_{(a q)}^{-}

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H_{2} S O_{4} (a q) + H_{2} O (l) ⇌ H_{3} O^{+} (a q) + H S O_{4}^{-} (a q)

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