In which of the following reaction white precipitate is obtained?

F e C l_{3} (a q) + N H_{4} O H (a q) \to

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Z n S O_{4} (a q) + N H_{4} O H (a q) \to

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C u^{2 +} (a q) + N H_{3} (a q) \to

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A g C l (s) + N H_{3} (a q) \to

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Solution

The correct option is B $Z n S O_{4} (a q) + N H_{4} O H (a q) \to$
$Z n S O_{4} (a q) + 2 N H_{4} O H (a q) \to Z n (O H)_{2} (s) White precipitate + (N H_{4})_{2} S O_{4} (a q)$

$F e C l_{3} (a q) + N H_{4} O H (a q) \to F e_{2} O_{3} . x H_{2} O (s) Brown precipitate + N H_{4} C l (a q)$

$C u^{2 +} (a q) + 4 N H_{3} (a q) \to [C u (N H_{3})_{4}]^{2 +} (Deep blue) (a q)$

$A g C l (s) + 2 N H_{3} (a q) \to [A g (N H_{3})_{2}] C l (a q) (Colourless)$

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In which of the following reaction white precipitate is obtained?

The correct option is B ZnSO4(aq)+NH4OH(aq)→ZnSO4(aq)+2NH4OH(aq)→Zn(OH)2(s)White precipitate+(NH4)2SO4(aq) FeCl3(aq)+NH4OH(aq)→Fe2O3.xH2O(s)Brown precipitate+NH4Cl(aq) Cu2+(aq)+4NH3(aq)→[Cu(NH3)4]2+(Deep blue)(aq) AgCl(s)+2NH3(aq)→[Ag(NH3)2]Cl(aq)(Colourless)