Question

In which of the following reactions does $N{H}_3$ act as an acid ?

• A. $N{H}_3$ + $H^{+}$ $⟶$ ${N{H}_4}^{+}$
• B. $N{H}_3$ + Na $⟶$ $NaN{H}_2$ + $\frac{1}{2}$ $H_2$
• C. $N{H}_3$ + HCl $⟶$ $N{H}_{4}Cl$
• D. None of these

Answer 1

The correct option is B

$N{H}_3$ + Na $⟶$ $NaN{H}_2$ + $\frac{1}{2}$ $H_2$

In the following reaction, $N{H}_3$ changes to $NaN{H}_3$ which contains ${N{H}_2}^{-}$ ion. This means that $N{H}_3$ has donated a proton to Na and hence acts as an acid.