In which of the following reactions does NH 3 act as an acid-A- NH 3- H - NH 4-B- NH 3- Na - NaNH 2-1-2 H 2C- NH 3- HCl - NH 4 ClD- None of these

The correct option is B In the following reaction, NH_3 nbsp;changes to NaNH_3 nbsp;which contains NH_2^ ion. This means that NH_3 nbsp;has donated a ...

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Byju's Answer

Standard X

Chemistry

Neutralisation Reaction

In which of t...

Question

In which of the following reactions does $N H_{3}$ act as an acid ?

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None of these

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Solution

The correct option is B

In the following reaction, $N H_{3}$ changes to $N a N H_{3}$ which contains ${N H_{2}}^{-}$ ion. This means that $N H_{3}$ has donated a proton to Na and hence acts as an acid.

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Similar questions

Q. From the following reactions identify each of an Arrhenius acid or base, Bronsted-Lowry acid or base, or Lewis acid or base.
(A)

N a O H

, in

N a O H \to {N a}^{+} + {O H}^{-}

(B)

H C l

, in

H C l \to H^{+} + {C l}^{-}

(C)

N H_{3}

, in

N H_{3} + H^{+} \to N H_{4}^{+}

(D)

N H_{4}^{+}

, in

N H_{4}^{+} \to N H_{3} + H^{+}

(E)

{(C H_{3})}_{3} N :

, in

{(C H_{3})}_{3} N : + B F_{3} \to {(C H_{3})}_{3} N : B F_{3}

In which of the following reactions does $N H_{3}$ act as an acid ?

State True or False.

Out of the following acid base-reactions, reaction (b) and(c) are possible.
a.

P H_{3} + \oplus N H_{4} ⟶ \oplus P H_{4} + N H_{3}

N H_{3} + P {\oplus H}_{4} ⟶ N {\oplus H}_{4} + P H_{3}

(C H_{3})_{3} P + \oplus N H_{4} ⟶ (C H_{3})_{3} \oplus P H + N H_{3}

(C H_{3})_{3} N + P H_{4}^{\oplus} ⟶ (C H_{3})_{3} \oplus N H + P H_{3}

Q. Which is/are not correct variation of indicated properties in

N H_{2}^{-}, N H_{3}

and

N H_{4}^{+}

Q. Autoprotolysis constant of

N H_{3}

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In which of the following reactions does NH3 act as an acid ?

The correct option is B In the following reaction, NH3 changes to NaNH3 which contains NH2− ion. This means that NH3 has donated a proton to Na and hence acts as an acid.

In which of the following reactions does $N H_{3}$ act as an acid ?

The correct option is B

In the following reaction, $N H_{3}$ changes to $N a N H_{3}$ which contains ${N H_{2}}^{-}$ ion. This means that $N H_{3}$ has donated a proton to Na and hence acts as an acid.