The correct options are
B H2O2−2e−⟶O2+2H+
D H2O2+2OH−−2e−⟶O2+2H2O
Losing or giving away electrons reduces the oxidation number/state of the species with which
H2O2 reacts. Hence, in those cases, H2O2 will be acting as a reducing agent.
Thus:
H2O2−2e−⟶O2+2H+
H2O2+2OH−−2e−⟶O2+2H2O