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In which of t...

Question

In which of the following reactions, hydrogen peroxide acts as an oxidizing agent?

H O C l + H_{2} O_{2} \to H_{3} O^{+} + C l^{-} + O_{2}

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2 M n O_{4}^{-} + 3 H_{2} O_{2} \to 2 M n O_{2} + 3 O_{2} + 2 H_{2} O + 2 O H^{-}

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P b S + 4 H_{2} O_{2} \to P b S O_{4} + 4 H_{2} O

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I_{2} + H_{2} O_{2} + 2 O H^{-} \to 2 I^{-} + 2 H_{2} O + O_{2}

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Solution

The correct option is C $P b S + 4 H_{2} O_{2} \to P b S O_{4} + 4 H_{2} O$
$P b S + 4 H_{2} O_{2} \to P b S O_{4} + 4 H_{2} O$
In the above reaction, $H_{2} O_{2}$ acts as an oxidizing agent. It oxidizes $P b S$ to $P b S O_{4}$ . $H_{2} O_{2}$ itself is reduced to $H_{2} O$
Note: Addition of oxygen is oxidation and removal of oxygen is reduction.

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Similar questions

(A) H O C l + H_{2} O_{2} \to H_{3} O^{+} + C l^{-} + O_{2}

(B) I_{2} + H_{2} O_{2} + 2 O H^{-} \to 2 I^{-} + 2 H_{2} O + O_{2}^{-}

H_{2} O_{2}

(a)

H_{2} O_{2} + 2 H^{+} + 2 e^{-} \to 2 H_{2} O

(b)

H_{2} O_{2} - 2 e^{-} \to O_{2} + 2 H^{+}

(c)

H_{2} O_{2} + 2 e^{-} \to 2 O H^{-}

(d)

H_{2} O_{2} + 2 O H^{-} - 2 e^{-} \to O_{2} + 2 H_{2} O

H_{2} O_{2}

H_{2} O_{2} + 2 H^{+} + 2 e^{-} \to 2 H_{2} O

H_{2} O_{2} - 2 e^{-} \to O_{2} + 2 H^{+}

H_{2} O_{2} + 2 e^{-} \to 2 O H^{-}

H_{2} O_{2} + 2 O H^{-} 2 e^{-} \to O_{2} + 2 H_{2} O

H_{2} O_{2}

H_{2} O_{2} + 2 H^{+} + 2 e \to 2 H_{2} O

H_{2} O_{2} - 2 e \to O_{2} + 2 H^{+}

H_{2} O_{2} + 2 e \to 2 (O H^{-})

H_{2} O_{2} + 2 O H^{-} - 2 e \to O_{2} + 2 H_{2} O

H_{2} O_{2}

H_{2} O_{2} + 2 H^{+} + 2 e^{-} \to 2 H_{2} O

H_{2} O_{2} - 2 e^{-} \to O_{2} + 2 H^{+}

H_{2} O_{2} + 2 e^{-} \to 2 O H^{-}

H_{2} O_{2} + 2 O H^{-} - 2 e^{-} \to O_{2} + 2 H_{2} O

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