You visited us 1 times! Enjoying our articles? Unlock Full Access!

Le Chatelier's Principle for Del N Equals to 0

In which of t...

Question

In which of the following reactions, increase in the pressure at constant temperature does not affect the moles at equilibrium?

2 N H_{3} (g) ⇌ 2 N_{2} (g) + 3 H_{2} (g)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C (g) + \frac{1}{2} O_{2} (g) ⇌ C O (g)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

H_{2} (g) + \frac{1}{2} O_{2} (g) ⇌ H_{2} O (g)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

H_{2} (g) + I_{2} (g) ⇌ 2 H I (g)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $H_{2} (g) + I_{2} (g) ⇌ 2 H I (g)$
In the reaction of option D, the total number of moles of reactants is equal to the number of moles of product. For such reactions, when pressure is changed, there is no change in equilibrium.

Suggest Corrections

Similar questions

Δ H

k J

C (g) + O_{2} (g) \to C O_{2} (g)

H_{2} O (g) + C (g) \to C O (g) + H_{2} (g)

Δ H = + 131 k J

C O (g) + \frac{1}{2} O_{2} (g) \to {C O}_{2} (g)

Δ H = - 282 k J

H_{2} (g) + \frac{1}{2} O_{2} (g) \to H_{2} O (g)

Δ H = - 242 k J

H_{2_{(g)}} + I_{2_{(g)}} ⇌ {2 H I}_{(g)}

{2 H I}_{(g)} ⇌ H_{2_{(g)}} + I_{2_{(g)}}

N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g); K_{1}

N_{2} (g) + O_{2} (g) ⇌ 2 N O (g); K_{2}

H_{2} (g) + \frac{1}{2} O_{2} (g) ⇌ H_{2} O (g); K_{3}

2 N H_{2} (g) + \frac{5}{2} O_{2} (g) ⇌ 2 N O (g) + 3 H_{2} O (g)

H_{2} O (g) ⇌ H_{2} (g) + \frac{1}{2} O_{2} (g), Δ H^{\circ} = 200 k J m o l^{- 1} Δ S^{\circ} = 40 J m o l^{- 1}

N_{2} (g) + H_{2} (g) ⇌ 2 N H_{3} (g); K_{1}

N_{2} (g) + O_{2} (g) ⇌ 2 N O (g); K_{2}

H_{2} (g) + \frac{1}{2} O_{2} (g) ⇌ H_{2} O (g); K_{3}

N H_{3}

N O

2 N H_{3} (g) + \frac{5}{2} O_{2} (g) ⇌ 2 N O (g) + 3 H_{2} O (g)

Join BYJU'S Learning Program