In which of the following reactions, only single isomer of alkene is formed?

C_{6} H_{5} - C H_{2} - C H_{2} - C H_{2} - B r K O H - ---- \to E t h a n o l

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C_{6} H_{5} - C H_{2} - B r | C H - C_{6} H_{5} K O H - ---- \to E t h a n o l

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Solution

The correct option is A $C_{6} H_{5} - C H_{2} - C H_{2} - C H_{2} - B r K O H - ---- \to E t h a n o l$
Dehydrohalogenation involves removal of (elimination of) a hydrogen halide by abstracting $β - H$ from a alkyl halide in presence of base (alc. KOH) to form alkenes.
option 'a' has only one type of $β - H$ and product alkene does not have stereoisomers.
(b) forms pair of geometrical isomers (cis and trans) after dehydrohalogenation.
(c) does not form alkene in the given condition as it does not have any $β - H$ .
(d) has more than one types of $β - H$ and forms more than one products (more substituted one will be major).
Hence option 'a' is correct.

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