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Question

In which of the following reactions, only single isomer of alkene is formed?

A
C6H5CH2CH2CH2BrKOH−−−−Ethanol
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B
C6H5CH2Br|CHC6H5KOH−−−−Ethanol
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C
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D
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Solution

The correct option is A C6H5CH2CH2CH2BrKOH−−−−Ethanol
Dehydrohalogenation involves removal of (elimination of) a hydrogen halide by abstracting βH from a alkyl halide in presence of base (alc. KOH) to form alkenes.
option 'a' has only one type of βH and product alkene does not have stereoisomers.
(b) forms pair of geometrical isomers (cis and trans) after dehydrohalogenation.
(c) does not form alkene in the given condition as it does not have any βH.
(d) has more than one types of βH and forms more than one products (more substituted one will be major).
Hence option 'a' is correct.

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